Question

Probability of getting a stum greation thon 9 in 1 throw of pair of dise. is unur we gel
[
(4,6) ;(6,4),(5,5)=frac{3}{36}=frac{1}{12}
]
Now succan have 5 cases Casel : sum less than 9 in 1 st throw
Fo each case proot. is ( left(frac{1}{12}right)^{4} times frac{11}{12} ) So total probability ( =5 timesleft(frac{1}{12}right)^{4} timesleft(frac{11}{12}right) )
[
=frac{55}{12^{5}}
]

# Find the probability of getting a total greater than 9 four times, in five throws of a pair of fair six-faced dice.

Solution