Question
Da
sel? ( (3 y-2)+i(7-2 x)=0 )
or ( (3 y-2)+i(7-2 x)=0+0 i )
on comparing both sides ( rightarrow ) ( 3 y-2=0 quad & quad 7-2 x=0 )
( Rightarrow quad y=frac{2}{3} quad & quad x=frac{7}{2} )
( 80, quad x=frac{7}{2}, quad y=frac{2}{3} )

Find the real value of nandy, =) (34_() + "[7-2x) =0
Solution
