Question
( (k-12) x^{2}+2(k-12) x+2=0 )
equation nas zeal nots if ( b^{2}-4 a c=0 )
( [2(k-12)]^{2}-4(k-12] 2=0 )
( x(k-12)[(k-12)-2]=0 )
( k=12 ) or ( K-14=0 )
( k=14 )
for ( k=12,14 ) equation has real ( x 006 )

Find the values of k for which the following equation has equal roots : (k-12) x2 +2 (k-12)x+2 = 0
Solution
