For a chemical reaction, given that...
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For a chemical reaction, given that logo k =15-1000 K Then select the correct statements. (a) activation energy of the reaction is 19.15 kJ (b) graph between log10 k (y-axis) and I (x-axis) will be a straight line with negative slope (c) Arrhenius constant (A) will be 10- A a, b, c all are correct B Only a is correct C Only b is correct

JEE/Engineering Exams
Chemistry
Solution
26
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( log _{10} R=15-frac{1000}{T} quad R=A e^{-[a mid R T} ) ( log k=log A-frac{E a}{2.303 R T} ) ( operatorname{Companing} frac{1000}{K}=frac{E a}{2.303 R J} ) ( begin{aligned} E_{a}=& frac{2.303 times 1000 times 8.314}{860} &=2 A 71003 mathrm{J} 19147.142 mathrm{J} end{aligned} ) ( =10.12 x times k J ) ( 19.147 mathrm{kJ} ) Ael Corect ( (a, b, c) )
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