Question
( k=k cos ^{2} omega t )
( k_{operatorname{man}}=k ) for ( omega t=0 )
un s.tim when p.E is man
( k cdot E=0 )
tet total Enorgy be E
( E=k cdot E_{m n}+U_{n m} )
( frac{|E=k|+0}{text { for } k in operatorname{mon}}=0 )
i. ( frac{10}{e^{10}=k} )

For a particle executing SHM. The KE 'K' is given by K = K, cos2 wt. The maximum value of PE is
Solution
