Question

formation of the hydrocarbon. 12. A sample of a gaseous hydrocarbon occupying 1.12 litres at NTP when completely burnt in air produced 2.2 g of CO2 and 1.8 g of H-0. Calculate the weight of the compound taken and the volume of O2 at NTP required for its burning. Find the molecular formula of the hydrocarbon. its found to have

JEE/Engineering Exams

Chemistry

Solution

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Let the fermula if hydrocarbon be ( C x^{H} y ) " [ left.c x H y rightarrowleft[x+left(frac{y}{4}right)right] 0,2 rightarrow x(0,-1 / 4)right] 4,0 ] ( 22 cdot 4 ) litre of ( c x ) ny on cornbulshon 7 iveg ( 44 x, 260 ) ( therefore quad 1 cdot 12 ) litre of ( c x ) hy on combuls orm Sirorilariy, "? ( 22 cdot 4 ) idres of ( c x+1 y ) indes ( 18 timesleft(frac{y}{2}right) partial^{H}_{2} 0 ) ( therefore ) iste nexply gives ( 18 times frac{8}{2} times frac{1012}{22 cdot 4} 2420=frac{8 times 10}{40} ) ( therefore quad 1: 8=left(frac{18}{40}right) times b quad: 15 quad 2-4 ) ( therefore ) Hy alro carbon is c 44 , ronethane