From a building two balls ( A ) and ( B ) are thrown such that ( A ) is thrown upwards ( A ) and ( B ) downwards (both vertically). If ( mathrm{V}_{mathrm{A}} ) and ( mathrm{V}_{mathrm{B}} ) are their respective velocities on reaching the ground, then ( quad )
( (A) V_{B}>V_{A} )
(B) ( V_{A}=V_{B} )
(C) ( V_{A}>V_{B} )
(D) their velocities depend on their masses

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Using the concentration of energy the
ie PE = at height h equals K.E at ground.
[
begin{array}{c}
Rightarrow m_{A} g h=left(m_{A} v_{A}^{2}right) / 2
V_{A}=sqrt{2} g h
end{array}
]
Smnilelly
[
V_{B}=sqrt{2} g h
]
[
V A=V B
]

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