Given standard electrode potentials...
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Given standard electrode potentials Fe2+ + 2e -> Fe E° = 0.440V Fe3+ + 3e > Fe E° =-0.036V The standard electrode potential (E°) for Fe3+e- >Fe2+

JEE/Engineering Exams
Chemistry
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( x_{c}^{3+}+e^{-} longrightarrow F_{c}^{2 t} quad E^{0}=-0.476 mathrm{V} )
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