Question

We know that ( mathrm{HCF}(mathrm{a}, mathrm{b}) times mathrm{LCM}(mathrm{a}, mathrm{b})=mathrm{a} times mathrm{b} )
( Rightarrow L C M(a, b)=frac{a times b}{H C F(a, b)} )
( therefore operatorname{LCM}(306,657)=frac{306 times 657}{mathrm{HCF}(306,657)} )
( =frac{306 times 657}{9}=34 times 657=22338 )

# Given that HCF (306,657)=9, find L.C.M(306,657).

Solution