Question

# Given that HCF (306,657)=9, find L.C.M(306,657).

Solution

We know that
HCF (a, b) XLCM(a, b)= a xb
axb
=LCM(a, b) = HCF(a, b)
306 x 657
| :. LCM (306, 657)=
HCF (306, 657)
306 x 657
= 34 x 657 = 22338
Solution

We know that
HCF (a, b) XLCM(a, b)= a xb
axb
=LCM(a, b) = HCF(a, b)
306 x 657
| :. LCM (306, 657)=
HCF (306, 657)
306 x 657
= 34 x 657 = 22338