Question

( begin{aligned} sqrt{3}=sqrt{6 / 2} &=frac{sqrt{6}}{sqrt{2}}=frac{2.449}{1.414}=1.732 sqrt{3}-sqrt{2}-1=& 1.732-1.414-1 =& 1.732-2.414 =&-0.682 frac{1}{sqrt{3}-sqrt{2}-1} &=frac{1}{0.682} &=-1.466 end{aligned} )

# Given, v2 = 1.414 and 16 = 2.449, find the value of to 3 places of decimal. 3-12-1 correct [2014]

Solution