Question

( sin 2 x=sin frac{3 pi}{2}=-1 )
( sin x=frac{1}{sqrt{2}} )
( tan frac{3 pi}{4}=- )
( f(n)=frac{1}{sqrt{b-a}} sqrt{frac{sqrt{frac{b-a}{a}} cdot(-1)}{1+(sqrt{left.frac{b-a}{2 a}right)^{2}}}{sqrt{a+b}}} )
( =frac{-1}{sqrt{b-a}} frac{sqrt{b-a}-sqrt{b+a}}{sqrt{1+frac{b-9}{2 a}}} )
( =-frac{sqrt{2} sqrt{b-9} sqrt{b+a}}{sqrt{b-a} cdot sqrt{a+b}} cdot frac{sqrt{a}}{sqrt{a}} )
( =-sqrt{2} )

# ha sin 2x 6. The value of the expression f(x) = btan? (b> a > 0) when x = b - а 1+ sinx is (A) 2 (B)- 2 (C) 1 (D) non existent

Solution