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Helle, d y J 3 W ICU spuis on all the three wheels touch the ground. Find the largest number that will divide 398, 436 and 542 leaving remainders 7,11 and 15 respectively.

NEET/Medical Exams
Maths
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Solution
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Clearly, the required number is the H.C.F of the numbers 2007=391.436-11=425. and 542-15= 527. First we find the H.C.F. of 391 and 425 by Euclid's algorithm as given below: 425= 391 1+34 391 = 3411 +17 34 =172+0 Clearly, H.C.F of391 and 425 is 17. Let us now find the H.C.F of 17 and the third number 527 by Euclid's algorithm: 527=17*31 +0 The H.C.F of 17 and 527 is 17. Hence, H.C.F of 391,425 and 527 is 17. Hence, the required number is 17.
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