Question

caseli) ( div ) Let ( x ) be ( +v e )
Then
[
begin{aligned}
x geq 1 & ; x-1<3
& Rightarrow x<4
1 leq x &<4
end{aligned}
]
Jhus, ( quad x={1,2,3} )
Am: ( exists y x ) is integer then ( x={-1,1,2,3} )
gf ( x in R, ) then (-2,-1]( cup[1,4) )

# I 1X21 Solve simultaneously: 11x-11<3

Solution