Question

( 4.3^{x}-1=3^{2 x+1} )
( 4.3^{x}-1=3^{2 x} cdot 3 )
( 3^{2 x}(3)-3^{x(4)}+1=0 )
( 3^{x}=frac{4 pm sqrt{16-4(3)}}{6}=frac{6}{6}, frac{2}{6} )
( =frac{4 pm 2^{2}(3)}{6}=1, frac{1}{3}=sqrt{x=0,-1} )

# iü. log,(4.3x - 1) = 2x + 1

Solution