I motion, the x&y 0.74 remain in al...
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I motion, the x&y 0.74 remain in all TU W JW puru IfTis the total time of flight, h is the maximum height & R is the range for horizontal motion co-ordinates of projectile motion and timet are related as: (4) y = 4 (2)(1-2) (©) y=4h() (1-1) (B) y=4h) (1 - (D) y= 41 (*) (1 - lati Ate

JEE/Engineering Exams
Physics
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( mathrm{y}=mathrm{xtan}(theta)-frac{mathrm{gx}^{2}}{2 mathrm{u}^{2} cos ^{2} theta} ) ( mathrm{R}=frac{mathrm{u}^{2} sin 2 theta}{mathrm{g}}, mathrm{H}=frac{mathrm{u}^{2} sin ^{2} theta}{2 mathrm{g}} mathrm{u} operatorname{sing} ) them we have ( mathrm{H} / mathrm{R}=frac{frac{u^{2} sin ^{2} theta}{2_{5}}}{frac{n^{2} sin 2 phi}{5}}=frac{sin theta}{4 cos theta} ) orH ( / mathrm{R}=frac{tan theta}{4} ) while ( mathrm{H} / mathrm{R}^{2}=frac{frac{mathrm{n}^{2} mathrm{sin}^{2} theta}{2 mathrm{g}}}{left(frac{mathrm{s}^{2} mathrm{sin} 2 mathrm{g}}{mathrm{k}}right)^{2}}=frac{mathrm{g}}{8 mathrm{u}^{2} cos ^{2} theta} ) or ( 8 mathrm{H} / mathrm{R}^{2}=frac{mathrm{g}}{mathrm{u}^{2} cos ^{2} theta} ) so ( mathrm{y}=4 mathrm{H}(mathrm{x} / mathrm{R})(1-(mathrm{x} / mathrm{R}))=frac{4 mathrm{H}}{mathrm{R}} mathrm{x}-frac{4 mathrm{H}}{mathrm{R}^{2}} mathrm{x}^{2} ldots ldots(1) )
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