Question

( x )
( { }^{B} pi^{V_{1}} )
( left(begin{array}{c}triangle 40^{circ} 0end{array}right)^{text {A Resolving } vec{V}_{2} text { along }} )
( begin{aligned} overrightarrow{v_{2}}=& x_{2} cos 40^{circ} hat{g}-v_{2} sin 40^{circ} hat{u} vec{v}_{1} &=v_{1} hat{g} text { Chonge in velocity } &=v_{2}-vec{v}_{1} end{aligned} )
( -v_{2} sin theta_{0}^{0} hat{u} )
( =v_{2} cos 40^{circ} hat{g}-v_{1} hat{g} )

# ICLO on Bank)SAT01-Physics.p65 A person is moving in a circle of radius r with constant speed v. The change in velocity in moving from A to B is (1) 2 v cos 40° (2) 2 v sin 40° (3) 2 v cos 20° (4) 2 v sin 20° 040°

Solution