Question
liven molecules ( =3 cdot 011 times 10^{23} mathrm{molecul} )
of solute No of moles
[
text { of solute }=frac{3 cdot 011 times 10^{23}}{6 cdot 023 times 10^{23}}
]
( =0.5 ) moles
Molarity = Moles
[
frac{-0.5}{0.7}=frac{5}{7}=0.71 M
]

If 3.011x1023 molecules of a solute all dissch water to prepare 700mL solution. The mola the solution is
Solution
