If 3.011x1023 molecules of a solute...
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If 3.011x1023 molecules of a solute all dissch water to prepare 700mL solution. The mola the solution is

IIT/JEE
Chemistry
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liven molecules ( =3 cdot 011 times 10^{23} mathrm{molecul} ) of solute No of moles [ text { of solute }=frac{3 cdot 011 times 10^{23}}{6 cdot 023 times 10^{23}} ] ( =0.5 ) moles Molarity = Moles [ frac{-0.5}{0.7}=frac{5}{7}=0.71 M ]
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