Question

( 3^{x}=4^{x-1} )
Talking doga both side ( ln sqrt{3} x log _{2} 3^{x}=log _{2} 4^{x-1} )
( x log _{2} 3=(x-1) log _{2} 4 )
( x log _{2} 3=(x-1) times 0 quad log _{2} 2^{2} )
( x log _{2}^{3}=(x-1) times 2 log _{2} 2^{2} )
( x log _{2} 3=2(x-1) )
( x log _{2} 3=2 x-2 )
( 2=xleft[2-log _{2} 3right] )
( int x=frac{2}{2-log _{2} 3} )
(B) Ophion is rorred

# If 3x = 4x-1, then x = MCQ [IIT-Advanced 2013] 2 log 3 2 2 (B) – 2log 2-1 2 - log23 2 log23 (D) 2log, 3-1 (C) 1-log43

Solution