Question

( (4 a+c)^{2}-4 b^{2}<0 )
( (4 a+c-2 b)(4 a+c+26)<0 )
( f(2) quad f(-2)<0 )
so one Rot lues un (-2,2)

# If (4a + c)2 < 4b2 then one root of ax2 + bx + c = 0 lies in (2) (-1, 1) (1) (-2, 2) (4) (2,00) (3) (0, -2) ob the

Solution