Question
( begin{array}{l}A=left[begin{array}{cc}4 & 8 -2 & -4end{array}right] A^{2}=A cdot A=left[begin{array}{cc}4 & 8 -2 & -4end{array}right]left[begin{array}{cc}4 & 8 -2 & -4end{array}right] = & left(begin{array}{ccc}16-16 & 32-32 -8+8 & -16+16end{array}right)=left[begin{array}{cc}0 & 0 0 & 0end{array}right] A^{2}=0 & =0end{array} )

If A= 5 4 L-2 87 , prove that AP=0. -4 P
Solution
