If A⋅B=|A×B|, angle between A and B...
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If ( overrightarrow{mathrm{A}} cdot overrightarrow{mathrm{B}}=|overrightarrow{mathrm{A}} times overrightarrow{mathrm{B}}|, ) angle between ( overrightarrow{mathrm{A}} ) and ( overrightarrow{mathrm{B}} ) is
(a) ( 180^{circ} )
(b) ( 90^{circ} )
( (c) 0^{circ} )
( (d) 45^{circ} )

NEET/Medical Exams
Physics
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If A⋅B=|A×B|, angle between A and B is
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( vec{A} . vec{B}=|vec{A}||B| cdot cos theta )
( vec{A} times vec{B}=|vec{A}| cdot|vec{B}| cdot sin theta mid )
( So_{} vec{A} cdot vec{B}=|vec{A} times vec{B}| )
( begin{aligned} A|A||B| cos theta=|A||B|  &=sin theta cos theta &=sin{theta} therefore quad theta &=45 end{aligned} )

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