Question
( A+B=90-C )
( cot (A+B)=cot (90-C) )
( frac{cot A(theta+B-1}{cot B+cot A}=tan C )
( frac{cot A cot B-1}{cot B+cot A} d x sin B+cot A=frac{1}{cot C} )
( cot C[cot A cos t B-1]=cot B+cot A )
( cot c cot A cot B-cot C=cot B+A cot A )
( cot A cot B cot C=cot A+cot B+cot C )

if (A+B+C) = 90 then cot At Cot B t cote Cat A Cat B Cote
Solution
