Question

area of shaded ( =pi R^{2}-frac{sqrt{3} cdot a^{2}}{4} cdot )
( cos 120^{circ}=frac{R^{2}+R^{2}-a^{2}}{2 R^{2}}=frac{-1}{2} )
( 2 R^{2}-a^{2}=-R^{2} )
( =1 quad a^{2}=3 R^{2} )
( therefore ) avea nuaded ( =pi R^{2}-frac{3 sqrt{3} R^{2}}{4} )
( =(4 pi-3 sqrt{3}) R^{2} )
ofive rating
A) Ans. refardo iltiom

# If an equilateral triangle is inscribed in a circle of radius R as shown in the figure, then the area of the shaded region in square units, is! (A) (47–313)R (B) (4x+3/3) (c) (29-313)R (D) (41 -3/3)R

Solution