Question

( sec theta=x+frac{1}{4 x} )
( sec ^{2} theta=x^{2}+frac{1}{(4 x)^{2}+2 x x+4} )
( 1+tan ^{2} theta=x^{2}+frac{1}{(4 x)^{2}}+frac{1}{2} )
( tan ^{2} theta=x^{2}+frac{1}{(4 x)^{2}-frac{1}{2}} )
( tan theta=x-frac{1}{4 x} )
( sec theta+tan theta=x+frac{1}{4 x}+x-frac{1}{4 x}=2 x )

# If sec 0 = x + -- then prove that sec 0 + tan 0 = 2x or

Solution