Question
( sin theta=-frac{4}{5} )
( cos theta=-frac{3}{5} )
( cos 2 theta=2 cos ^{2} theta-1 )
( Rightarrow cos theta=2 cos ^{2} frac{theta}{2}-1 )
( Rightarrow cos ^{2} frac{theta}{2}=-frac{cos theta+1}{frac{2}{frac{3}{2}}-frac{1}{sqrt{5}}} )
( =-sqrt{-frac{3}{2}} )

If sin 0 = - and e lies in IIIrd quadrant then the value of cos (b) v
Solution
