If ∫sin 5x cos 3x dx =-cos8x16 +A, ...
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If ∫sin 5x cos3x dx =-frac{cos8x}{16} +A, then A=(a)frac{sin2x}{16} +constant(b)-frac{cos2x} {4} +constant(c)Constant (d) None of these

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If ∫sin 5x cos 3x dx =-cos8x16 +A, then A=
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@If ∫sin 5x cos3x dx =frac{1}{2}∫ (sin8x+sin2x)dx=frac{-cos8x}{16} -frac{cos2x}{4}+c Qeuating to the given value , we get A=frac{-cos2x}{4}+c.  

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