Question

MOlan mass of ( C_{6} H_{12} 0_{6}=6 times 12+1 times 1,2+16 times 6 )
( =180 mathrm{g} / mathrm{mol} )
( therefore quad ) no. ( g ) moteog Glucor per poil lithe ( =frac{0.99}{1800} ) notelL
[
begin{array}{l}
text { : Matity = } frac{text { no. g meles }}{text { volume }}
qquad begin{aligned}
&=frac{0.005 mathrm{m}}{1 mathrm{L}}
&=0.005 mathrm{M}
end{aligned}
end{array}
]

# If the concentration of glucose (C6H120) in blood is 0.9 g L-', what will be the molarity of glucose in blood 1) 5 M 2) 50 M 3) 0.005 M 4) 0.5 M

Solution