Question

( 2 x^{2}+k x+5=0 )
( x^{2}-3 x-4=0 )
( x^{2}-4 x+x-4=0 )
( quad quad x=4,-1 )
( 2-k eq 5=0 quad ) fo (-1) is ormon
[
begin{aligned} k-3 & text { root } 32+4 k-5=0 & text { If }(4) text { is common } 4 k=-27 & text { reft } k=-27 / 4 end{aligned}
]

# If the equation 2x2 + kx - 5 = Oand x2 – 3x - 4 = 0 have one root in common, then find the value of k. 11. - 4 .5x2

Solution