Question

Let us first find the H.C.F. of 210 and ( 55 . ) Applying Euclid's division lemma on 210 and ( 55, ) we get
[
210=55 times 3+45
]
since, the remainder ( 45 eq 0 . ) So, we now apply division lemma on the divisor 55 and the remainder 45 to get
( 55=45 times 1+10 )
We consider the divisor 45 and the remainder 10 and apply division lemma to get

# If the H.C.F of 210 and 55 is expressible in the form 210 x 5 + 55y, find y.

Solution