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Question

If the H.C.F of 210 and 55 is expressible in the form 210 x 5 + 55y, find y.

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Let us first find the H.C.F. of 210 and 55. Applying Euclid's division lemma on 210 and 55, we get 210=55x3+ 45 N ..... (i) Since, the remainder 45+0. So, we now apply division lemma on the divisor 55 and the remainder 45 to get 55=45 x 1 + 10 ..... (ii) We consider the divisor 45 and the remainder 10 and apply division lemma to get
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