Question

( frac{Delta D}{g} times 100=2 )
( T=frac{2 pi}{sqrt{g}} sqrt{2} )
( Delta T times 100=frac{1}{2}left(frac{Delta l}{2} times 100right) )
( T )
( frac{Delta T}{T} times 100=frac{1}{2} times 2=1 % )
Time period will be increased by ( 1 % )

# If the length of a second pendulum is increase by 2%, then in a day the pendulum 27

Solution