If the minimum value of x2 + 2x + 3...
Question
Fullscreen

If the minimum value of x2 + 2x + 3 is m and maximum value of – x2 + 4x + 6 is M then the value of m + M is (1) 10 (2) 11 (3) 12 (4) 13

JEE/Engineering Exams
Maths
Solution
166
Rating
4.0 (1 ratings)
Fullscreen
( n^{2}+2 n+3=m ) ( m^{2}+2 n+1-1+3=m ) ( (2+7)^{2}+2=m ) minimum value of ( m ) is 2 conom ( 6+7,2=0 ) ( -n^{2}+4 n+6=74 ) ( -left[n^{2}-4 n-6right]=M ) ( -sqrt{n^{2}-4 n+4-4-6}=n ) ( - sqrt { n - 2 , 2 } - 1 0 longdiv = 1 4 ) ( -[n-2]^{2}+10=n 1 ) Maximuma tam be when ( [n-2]^{2}=0 ) ( 1=10+2=12 )
Quick and Stepwise Solutions Just click and Send Download App OVER 20 LAKH QUESTIONS ANSWERED Download App for Free