Question

( 16 mathrm{t} C quad-8 mathrm{tt} C )
( a )
( therefore F_{0}=frac{K times 16 times 10^{-6} times 8 times 10^{-6}}{0^{2}}=108 times 10^{-12} mathrm{ak}_{2} mathrm{N} )
Whan to u ched ( frac{4 mu c}{(A)(R)} Rightarrow q=frac{-6+16}{2}+theta 4 u c )
( frac{C}{4 u C} )
9010
( therefore A_{N}=frac{k times 4 times 4 times 10^{-12}}{a^{2}}=frac{16 times 10^{-12} mathrm{kn}}{a^{2}} )
( i i+1 )

# If two identical spheres having charge 16 uC and -8 uC are kept at certain distance apart, then the force is F. They are touched and again kept at the same distance, the force becomes (1) F. 00177

Solution