Question

(A) Encrgy g photm = hf ( f=frac{c}{lambda}=frac{3 times 10^{8}}{4000 times 10^{-10}} )
( begin{aligned} E=frac{h c}{lambda}=frac{6 cdot 63 times 10^{-7} times 3 times 10^{8}}{4 times 10^{-7}}=frac{6.63 times 3 times 10^{-19}}{4} & frac{50.97 times 10^{-19}}{5^{-19}} &=5 times 10^{frac{10}{5}} end{aligned} )
oppion 2

# If wavelength of a photon is 4000 Å then the energy of that photon will be : (1) 0.5 * 10-19 J (2) 5 10-19 J Masoo (3) 0.5 * 1018 ] (4) 3 x 1020 J X4

Solution