Question

# If x= root of the polynomial f(x)=6r? - 11.x² + kx-20, then find the value of k.

Solution

Let f(x)=6r - 112° + kr -20
6.5 1 11.10 + 4h - 20=0
=>
►
128-176+12k-180=0
12k+128 - 356=0 => 12k=228 = k=19
Solution

Let f(x)=6r - 112° + kr -20
6.5 1 11.10 + 4h - 20=0
=>
►
128-176+12k-180=0
12k+128 - 356=0 => 12k=228 = k=19