Question

( phi(x)=phi^{prime}(x) rightarrow ) invowes ( f^{n} e )
( phi(1)=2 )
we need power of ( e ) to be 0 to get 1
( therefore phi(x)=2 e^{x-21} )
( therefore(x)=2 e^{x-4} 1 )
( therefore phi(1)=2 )
( therefore quad phi(3)=2 e^{3-1} )
( phi(3)=2 e^{2} )

# If (x) = '(x) and (1) = 2, then 0(3) equals (B) 2 e2 (C)3 e2 (D) 2 e3 (A) e2

Solution