Question

( x-y=frac{x+y}{7}=frac{x y}{4}=k(6 t) )
then ( x-y=k-0 )
and ( x+g=7 k-(2) )
( left.frac{2 x}{[x=4 k}right] )
( x+y=7 k )
( y=7 x-x=7 k-4 k )
( y=3 k )
we know that, ( x y=k )
( begin{array}{rl}x y & =4 k 4 k & x 3 k=4 k 3 k & =1 k & =frac{1}{3}end{array} )
( therefore x y=4 k=4 x frac{1}{3}=frac{4}{3} )
petion ( (A) )

# If x - y = * = , the numerical value of xy is: +0 WAIW -1+

Solution