Question
( x^{3}-3 x^{2}+3 x-7 )
( =a x^{3}+b x^{2}+c x )
( +a x^{2}+b x-varepsilon< )
Compare ( , a=1, b=-4 )
Corection
Inseed of ( +^{prime}, quad= ) sign
( 0.5 c=7 )
o ( 0 a+b+C=4 )

If x3 –3x2 + 3x – 7 =(x +1) (ax? + bx +c), then a+b+c= (a) 4 (b) 12 (c) - 10 (d) 3
Solution
