Question

( log _{3}|2 x-1|=1 )
( |2 x-7|=(3)=3 )
( 2 x-7=3 mid ; frac{-(2 x-7)}{2 x-7}=-3 )
( 2 x=10 )
( x=5 quad x=2,5 )

# If xi and x2 are two solutions of the equation log3 |2x - 71 = 1 where x1 < x2, then the number of integer(s) between xi and x2 is/are-

Solution