Question

( 200=200 )
( 120082-11=2008(2-4 )
( 12008 x-1+2008 y 11=20001 x+2+i y 1 )
( 12008 x-1)^{2}+(2008 y)^{2}=2008left((x-2)^{2}+y^{2}right) )
( Rightarrow 74 ) a cude

# If z is a complex number satisfying 2008z - 11 = 2008[z-21, then locus z is (1) y - axis oderun t (2) X- axis rez (3) Circle (4) A line parallel to y-axis Z2-1

Solution