Question

# II) Verily that 2. 1. I are the zeroes of -2- 2. Also verify the relationship between the zeres and the coetlieients.

Solution

se
.
X² - 2x²-x+ 2 = 0
S x²(x-2)(x-2) at
S (x-2)(x²-1) = 0
(x-2)(x-1)(x+1) = 0
So, x=2, 1,-1
Solution

se
.
X² - 2x²-x+ 2 = 0
S x²(x-2)(x-2) at
S (x-2)(x²-1) = 0
(x-2)(x-1)(x+1) = 0
So, x=2, 1,-1