iii. log (4.3* – 1) = 2x + 1
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iii. log (4.3* – 1) = 2x + 1

JEE/Engineering Exams
Maths
Solution
110
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( 4.3^{x}-1=3^{2 x+1} ) ( 4.3^{x}-1=3^{2 x} cdot 3 ) ( 3^{2 x}(3)-3^{x(4)}+1=0 ) ( 3^{x}=frac{4 pm sqrt{16-4(3)}}{6}=frac{6}{6}, frac{2}{6} ) ( =frac{4 pm 2^{2}(3)}{6}=1, frac{1}{3}=sqrt{x=0,-1} )
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