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# |x^{2} -3x+2|≤x-1

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|x²−3x+2|≤ x−1

x²--3x-x+2+1≤0

x²-4x+3≤0

x²-3x-x+3≤0

x(x-3)-1(x-3)≤0

⇒ (x-3)(x-1)≤0

So, x≤ 3, x≤1

**Thus, x≤1**

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