Question

In an organic compound of molar mass greater than 100 containing only C. H and N. the percentage of C is 6 times the percentage of H while the sum of the percentages of Cand His 1.5 times the percentage of N. What is the least molar mass?

JEE/Engineering Exams

Chemistry

Solution

244

5.0 (1 ratings)

( % ) of ( c=x, n=y quad & quad N=2 ) ( frac{x}{4}=6, x+4=1: 52, x=6 y ) - (ii i from (i) 4 [ begin{array}{c} 6 y+4=1 cdot 5 z 7 y=1 cdot 5 z 14 y=3 z frac{y}{y}=frac{14}{3} end{array} ] ( frac{x}{y}: frac{y}{7} ; frac{2}{7}=frac{5}{1}: 1 ; frac{14}{7} ) [ Rightarrow 18: 3: 14 ] mole ratio ( n ) o ( C ). ( mathrm{H} ); N ( frac{18}{12}: frac{3}{1}: frac{14}{14} ) ( 1 cdot 5: 3: 1 ) Simplest orido: ( sqrt{3}=6 quad therefore 2 ) Empirical bormana ig ( angle 3 mathrm{H}_{6} mathrm{N}_{2} ) rorss of ( mathrm{c}_{3} mathrm{H}_{6} mathrm{N}_{2}=70 ) given mol. Wh ( >107 ) ( therefore ) least value in 0 in ill be 2 therefore least mol wit will be [ 70 times 2=190 ]