Question

( begin{aligned} K_{E} m c x &=h v-phi &=frac{6 cdot 6 times 10^{-34} times 2-3 times 10^{15}-4}{1.6 times 10^{-19}} &=frac{6.6 times 2 cdot 3 times 10^{-15} times 10^{15}}{1.6} &=frac{6.6 times 2 cdot 3}{1.6} &=frac{0.4}{1.18} end{aligned} )

# in Choose the correct answer : bensiini The work function of a metal is 4 eV. If light of frequency 2.3 x 1015 Hz is incident on metal surface, then, (1) No photoelectron will be ejected (2) 2 photoelectron of zero kinetic energy are ejected (3) 1 photoelectron of zero kinetic energy is ejected (4) 1 photoelectron is ejected, which required the stopping potential of 5.52 volt

Solution