In the arrangement shown, the batte...
Question
In the arrangement shown, the battery is disconnected and a dielectric slab of dielectric constant K is inserted between the plates of capacitor with capacitance C,
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In the arrangement shown, the battery is disconnected and a dielectric slab of dielectric constant ( K ) is inserted between the plates of capacitor with capacitance ( C, ) so as to completely fill the space. What is the final potential difference across capacitor with capacitance ( 2 C ? )
(1) Zero
(2) ( V )
(3) ( frac{3 V}{2+K} )
(4) ( frac{V}{K+2} )

JEE/Engineering Exams
Physics
Solution
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In the arrangement shown, the battery is disconnected and a dielectric slab of dielectric constant K is inserted between the plates of capacitor with capacitance C, so as to completely fill the space. What is the final potential difference across capacitor with capacitance 2C?
Fullscreen

[
V_{A}-V_{B}=V
]
Va is connected directy ie. Shorteircu'ted ( V_{a}=v_{1}=v_{3}-c_{1} )
( v_{0}=v_{2}=v_{4}-t_{11} )
So now potential difference across
[
text { Caracitance } quad 2 c=V_{3}-V_{4}=V_{A}-v_{B}=1
]
So option 2 is - correct.

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