Question # In the arrangement shown, the battery is disconnected and a dielectric slab of dielectric constant ( K ) is inserted between the plates of capacitor with capacitance ( C, ) so as to completely fill the space. What is the final potential difference across capacitor with capacitance ( 2 C ? )

# In the arrangement shown, the battery is disconnected and a dielectric slab of dielectric constant ( K ) is inserted between the plates of capacitor with capacitance ( C, ) so as to completely fill the space. What is the final potential difference across capacitor with capacitance ( 2 C ? )

(1) Zero

(2) ( V )

(3) ( frac{3 V}{2+K} )

(4) ( frac{V}{K+2} )

Solution

[

V_{A}-V_{B}=V

]

Va is connected directy ie. Shorteircu'ted ( V_{a}=v_{1}=v_{3}-c_{1} )

( v_{0}=v_{2}=v_{4}-t_{11} )

So now potential difference across

[

text { Caracitance } quad 2 c=V_{3}-V_{4}=V_{A}-v_{B}=1

]

So option 2 is - correct.