In the circuit shown in the figure....
Question
In the circuit shown in the figure. E_1=10V,E_2=4V,r_1=r_2=1Ω and R=2Ω  Find the respective potential difference across battery 1 and battery 2
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In the circuit shown in the figure.
[
E_{1}=10 mathrm{V}, E_{2}=4 mathrm{V}, r_{1}=r_{2}=1 Omega text { and } R=2 Omega
]
Find the respective potential difference across battery 1 and battery 2
( A quad 5.5 vee ) each
B ( 8.5 mathrm{V} ) each
( mathrm{C} quad 5.5 mathrm{V}, 8.5 mathrm{V} )
D ( 8.5 vee, 5.5 vee )

JEE/Engineering Exams
Physics
Solution
87
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In the circuit shown in the figure. E_1=10V,E_2=4V,r_1=r_2=1Ω and R=2Ω  Find the respective potential difference across battery 1 and battery 2
Fullscreen

[
begin{array}{l}
E_{n c t}=10-4=6 V
r_{n c t}=r_{1}+r_{2}+R=1+1+2=4 Omega
i=frac{E_{n c t}}{r_{n e f}}=frac{6}{4}=frac{3}{2} A
end{array}
]
Poteutial difference across bathery ( 1=E_{1}-operatorname{lr} )
[
=10-frac{3}{2}(1)=frac{17}{2}=8 cdot 5 mathrm{V}
]
Poloutial difference acros battery ( 2=E_{2}+i r_{2} )
[
=4+frac{3}{2}(1)=frac{11}{2}=5 cdot 5 v
]
option (D)

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