Question

Let the total weight of the compound be ( mathrm{X} )
Then ( 20 % ) of ( X ) will be the weight of 2
nitrogen atoms = ( frac{20}{100} times X=14 times 2 )
( x=14 times 2 times frac{100}{20} )
( x=140 mathrm{gm} )

# J) 20.21U 41. A compound has 20% of nitrogen by weight. If one molecule of the compound contains two nitrogen atoms, the molecular weight of the compound is 1) 35 2) 70 3) 140 4) 280

Solution