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Lallude u VUIUITE Uluupituuy | MIUIU VIT What volume of oxygen (NTP) will be required to react with 1 g of Ca? A namnle of KCIO3 on decomposition yielded 448 mL of oxygen gas at N7

JEE/Engineering Exams
Chemistry
Solution
62
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( begin{array}{rl}2 mathrm{Ca}+mathrm{O}_{2} & 2 mathrm{CaO} 2 times 40 mathrm{g}left(mathrm{a}=22400 mathrm{cm}^{3} mathrm{O}_{2}right. therefore 1 mathrm{g}_{6}= & 22400 2 times 40 & mathrm{m}^{3} mathrm{O}_{2}end{array} )
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