Question

[
begin{array}{l}
Rightarrow quad N_{2}+3 n_{2} rightleftharpoons 2 N H_{3}
operatorname{lis}_{n} 1 / 2 frac{2}{2}
end{array}
]
t equili ( 2-frac{1}{2}=frac{3}{2} quad 2-frac{3}{2}=frac{1}{2} )
NO of moles of ( mathrm{Nh}_{3}=1 ) ( begin{aligned} text { Volume of vessel }=& 5 mathrm{L} therefore text { Gncentration }=& frac{N theta cdot theta text { moles }}{text { Volume }(L)} &=frac{1}{5}=0.2 mathrm{M} end{aligned} )

# Lars Two moles of N, and two moles of H, are taken in a closed vessel of 5 litres capacity and suitable conditions are provided for the reaction. When the equilibrium is reached, it is found that a half mole of N, is used up. The equilibrium concentration of NH, is (1) 03 (2) 04 (3) 02 (4) 0.1

Solution