Question

n is thon 2 to 10
. ( k ) will ( h ) LCM ob ( (2,3,1,5,6,7,8,9,10)-1 )
[
begin{array}{l}angle C M text { of }(2-10) text { is } 2520 k=250 quad 2520-1=2519end{array}
]
[
begin{array}{l}text { Sum ob digits }=2+5+1+9=17end{array}
]

# Let K be the smallest positive integer with the property that for all n such that 2 s s 10, when divided by it leaves a remainder of n - 1. then the sum of the digits of K equals. (A) 12 (B) 13 (C) 15 (D) 17

Solution